If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+42x-184=0
a = 1; b = 42; c = -184;
Δ = b2-4ac
Δ = 422-4·1·(-184)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-50}{2*1}=\frac{-92}{2} =-46 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+50}{2*1}=\frac{8}{2} =4 $
| 13+x/7=3 | | 9+3x=25-x | | -11/3(-5x+1/2)≥–66;x=–5 | | 6x/30+2x/10=50+25 | | 4-(2n+5)=10-7n-9 | | 3(x-3)=34-2(x+4) | | y+6=84 | | 10y+18=—3(5y-7)+5y | | (2x+7x)-(7x+x)=90 | | 4a=7=10 | | 3(4x+5)=-47+38 | | 4t+5=5t-5 | | 4x+8(-3x-8)5x-14;x=9 | | -3q+2P=10 | | 15x²+16x=15 | | P(1)=x4–4x3–7x2+22x+18 | | 4(4+a)=112 | | x*1.7=100 | | -5n-5=-40 | | (5x+7)-(2x+3)=-2x-9 | | 6x+11+46+105=180 | | 7x/15+5x/15=180 | | 9x+6+4x+6+90=180 | | 3m=5m-14 | | 3x-29=13x-19 | | 4x-7+3x-11+44=180 | | 4x+3x=940 | | (3x-11)(4x-7)44=180 | | (3x-11)(4x-7)44=18 | | -4y-7/4=3/4y-1/3 | | 3x+6x=540 | | 1/2(r-5)=8 |